|
Gender |
Sleep Apnea? |
||
|
yes |
no |
||
|
Men |
40 |
360 |
400 |
|
Women |
12 |
288 |
300 |
|
Total |
52 |
648 |
700 |
here is data from question 1. Need #2
Performing a Chi-Square test for statistical significance of independence between two categorical variables based on Question 1 (Using the same data as Question1).
a. For the Sleep apnea problem (Question 1), indicate the specific null and alternative hypotheses that will be used with a Chi-Square Test. Write the null hypothesis and alternative hypothesis for this 2 x 2 table.
b. Calculate the expected counts using the method shown in the example in the online notes 11.2 . Show all work. (Hint: Expected Count = n_row*n_column/n_total)
c. Interpret all four expected counts in the context of the problem.
(We would expect ____, if in fact there is no relationship between _____ and _____ in the population) You will have four answers–one for each expected count.
d. Calculate the Chi-Square Statistics by hand using the formula
e. Determine a p-value associated with the test statistics you calculated in previous question. Write down the degree of freedom and p-value from TABLE.
DF = (# rows -1) (# columns – 1)
p-value =
f. Confirm your p-value using Minitab. Copy and Paste your output.
[Hint: Minitab Express User: Statistics > Distribution Plots > Display Probability > Distribution > Chi-Square distribution > putting degree of freedom in the box > select “ a specified x value” > Right tail > Putting the chi-square statistics you calculated by hand > OK]
g. what is your conclusion based on your chi-square test? Reasoning?
